Sign vectors, as residues
15 = 3·5 gives 2² = 4; 1155 = 3·5·7·11 gives 2⁴ = 16 — one residue per ± choice across four places.
source
<notatio-cell value="PowerModList(1, 1 / 2, 15)" />
<notatio-cell value="PowerModList(1, 1 / 2, 1155)" />Hypercomplex algebras introduces i_k, j_k and ε_k as formal generators with a square attached. But you do not have to adjoin them — ℤ/m already contains them, and which ones it contains is decided one prime at a time. This page follows that all the way down.
The Chinese Remainder Theorem splits the ring: for
and a ring isomorphism carries
Counting is then immediate. For odd m,
with
15 = 3·5 gives 2² = 4; 1155 = 3·5·7·11 gives 2⁴ = 16 — one residue per ± choice across four places.
<notatio-cell value="PowerModList(1, 1 / 2, 15)" />
<notatio-cell value="PowerModList(1, 1 / 2, 1155)" />The rows of that second list are the sign vectors: 1 is
The clean law is stated for odd m because 2 misbehaves, and it misbehaves in a way worth seeing:
<notatio-cell value="PowerModList(1, 1 / 2, 2)" />
<notatio-cell value="PowerModList(1, 1 / 2, 4)" />
<notatio-cell value="PowerModList(1, 1 / 2, 8)" />
<notatio-cell value="PowerModList(1, 1 / 2, 16)" />Now ask the same question for
Half the primes qualify, by Dirichlet. This is the asymmetry that makes split units the generic case and imaginary units special — and it is the same asymmetry that makes
65 = 5·13, both ≡ 1 (mod 4), so two channels each contributing two roots. 15 = 3·5 has none: 3 ≡ 3 (mod 4) kills it.
<notatio-cell value="PowerModList(-1, 1 / 2, 5)" />
<notatio-cell value="PowerModList(-1, 1 / 2, 65)" />
<notatio-cell value="PowerModList(-1, 1 / 2, 15)" />Finding a root mod
is a root one power higher, and
Both of these are one head: Wolfram's PowerModList(a, 1/r, m), the
Three cube roots of 8 mod 13, because 3 divides 12.
<notatio-cell value="PowerModList(8, 1 / 3, 13)" />7² = 49 = 50 − 1, so 7 is the lift of 2 to ℤ/25; 182 is the lift to ℤ/625.
<notatio-cell value="PowerModList(-1, 1 / 2, 5)" />
<notatio-cell value="PowerModList(-1, 1 / 2, 25)" />
<notatio-cell value="PowerModList(-1, 1 / 2, 625)" />A split unit is not just a curiosity of ℤ/m: it is a homomorphism. If
respects addition and multiplication, so every identity the symbolic algebra proves becomes a fact about ℤ/m. The zero divisor and the idempotent both survive the trip:
Left: the symbolic identity. Right: its image under j ↦ 4 in ℤ/15.
<notatio-cell value="(1 + j_1) * (1 - j_1)" />
<notatio-cell value="(1 + 4) * (1 - 4) % 15" />
<notatio-cell value="((1 + j_1) / 2) ^ 2" />
<notatio-cell value="10 * 10 % 15" />This is why the idempotents matter. The split units, the CRT sign vectors and the orthogonal idempotents
Step back and the three columns of the grid stop looking like three arbitrary choices. Over a field, the quadratic algebra
| algebra | unit | |
|---|---|---|
| a square in | j | |
| a non-square | a quadratic field | i |
| zero | \epsilon |
So j, i and ε are not three unrelated inventions: they are the three outcomes of one construction, selected by whether
That is what the mod-m results above are really saying. Take
Whereas
The rings
so the CRT splitting at each finite level is the shadow of one product over all primes. Under that identification the split units assemble too: the elements of order dividing 2 in
Adjoining the archimedean place gives the adeles,
That is the direction, stated honestly as a direction: this page demonstrates the finite levels and the per-place criterion, and nothing here computes an adelic object. The pieces that would make it concrete — a Norm that names its ambient level, coefficients that live in ℤ/m rather than only mapping into it, and a per-place signature rather than one global square — are all still to build.